The Laplace Transformation (named after Pierre-Simon Laplace) is a useful mathematical tool that is used in many branches of engineering including signals and systems theory, control theory, communications, mechanical engineering, etc.
Its principle benefits are:
The only downside is that time $t$ is a real value whereas the Laplace transformation operator $s$ is a complex exponential $s = \sigma + j\omega$.
The preparatory reading for this session is Chapter 2 of Karris which
$$\mathcal{L}\{f(t)\}=F(s) = \int_{0}^{\infty}f(t)e^{-st}dt$$
$$\mathcal{L}^{-1}\{F(s)\}=f(t)=\frac{1}{2\pi j}\int_{\sigma-j\omega}^{\sigma+j\omega}F(s)e^{st} ds$$
The Laplace transform and its inverse come in pairs which are tabulated for ease of reference. For any given function of time $f(t)$ we only need to know the transform
$$f(t)\Leftrightarrow F(s)$$
to be able to get to the Laplace transform and vice versa.
$$c_1f_1(t) + c_2f_2(t) + \ldots + c_nf_n(t) \Leftrightarrow c_1F_1(s) + c_2F_2(s) + \ldots + c_nF_n(s)$$
$$f(t-a)u_0(t-a)\Leftrightarrow e^{-as}F(s)$$
$$e^{-at}f(t)\Leftrightarrow F(s+a)$$
$$f(at)\Leftrightarrow \frac{1}{a}F\left(\frac{s}{a}\right)$$
$$f'(t) = \frac{d}{dt} f(t) \Leftrightarrow sF(s) - f(0^-)$$
This property facilitates the solution of differential equations
$$tf(t) \Leftrightarrow -\frac{d}{ds}F(s)$$
and in general
$$t^nf(t) \Leftrightarrow (-1)^n\frac{d^n}{ds^n}F(s)$$
$$\int_{-\infty}^tf(\tau)d\tau \Leftrightarrow \frac{F(s)}{s}+\frac{f(0^-)}{s}$$
Providing that
$$\lim_{t\to 0} \frac{f(t)}{t}$$
exists
$$\frac{f(t)}{t}\Leftrightarrow \int_s^\infty F(s)ds$$
If $f(t)$ is a periodic function with period $T$ such that $f(t) = f(t+nT)$ for $n=1,2,3,\ldots$ then
$$f(t+nT) \Leftrightarrow \frac{\int_0^T f(t)e^{-st}dt}{1-e^{-sT}}$$
$$\lim_{t\to 0}f(t) \Leftrightarrow \lim_{s\to \infty} sF(s) = f(0^-)$$
$$\lim_{t\to \infty}f(t) \Leftrightarrow \lim_{s\to 0} sF(s) = f(\infty)$$
$$f_1(t)*f_2(t) = \int_{0}^{t}f_1(\tau)f_2(t-\tau) d\tau \Leftrightarrow F_1(s) F_2(s)$$
Multiplying two signals together in the time domain is the same as performing convolution in the complex frequency domain.
$$f_1(t)f_2(t) \Leftrightarrow \frac{1}{2\pi j}F_1(s) * F_2(s) = \frac{1}{2\pi j}\lim_{T\to \infty}\int_{c-jT}^{c+jT}F_1(\sigma)F_2(s-\sigma)d\sigma$$
Convolution in the complex frequency domain is nasty – multiplication in the time domain is relatively painless.
Every textbook that covers Laplace transforms will provide a tables of properties and the most commonly encountered transforms. Karris is no exception and you will find a table of transforms in Tables 2.1 and 2.2.
Here are a couple that are on the net for your reference
Tables of Laplace transform properties and transforms will be included with the exam paper.
f(t) | F(s) | |
---|---|---|
1 | $$\delta(t)$$ | $$1$$ |
2 | $$\delta(t-a)$$ | $$e^{-as}$$ |
3 | $$u_0(t)$$ | $$\frac{1}{s}$$ |
4 | $$t u_0(t)$$ | $$\frac{1}{s^2}$$ |
5 | $$t^n u_0(t)$$ | $$\frac{n!}{s^{n+1}}$$ |
6 | $$e^{-at}u_0(t)$$ | $$\frac{1}{s+a}$$ |
7 | $$t^n e^{-at} u_0(t)$$ | $$\frac{n!}{(s+a)^{n+1}}$$ |
8 | $$\sin (\omega t) u_0(t)$$ | $$\frac{\omega}{s^2 + \omega^2}$$ |
9 | $$\cos (\omega t) u_0(t)$$ | $$\frac{s}{s^2 + \omega^2}$$ |
10 | $$e^{-at} \sin (\omega t) u_0(t)$$ | $$\frac{\omega}{(s + a)^2 + \omega^2}$$ |
11 | $$e^{-at}\cos (\omega t) u_0(t)$$ | $$\frac{s+a}{(s+a)^2 + \omega^2}$$ |
Refer to the textbook if you want to see the proof of these transforms.
We will work through a few of the following on the board in class
The Matlab function laplace
can be used to find laplace transforms of time functions. The lab exercises will illustrate this.
Attempt at least one of the end-of-chapter exercises from each question 1-7 of Section 2.7 from the textbook. Don't look at the answers until you have attempted the problems.
If we have time, I will work through one or two of these in class.